TwoPlusTwo user Beck

Beck

Beck

veteran
Joined 20 years ago Lact Active: 9 days ago
1thread
22posts
1likes received

About

Location: Phuket, Thailand Interests: Occupation: Games and Stakes:

Probability 5mo ago

Winning at least two out of 5 trials, trials dependent on each other.

I'm a bit lost how to handle this. The situation is the following:

Card game with 36 cards (9 of each suit), 6 cards are known from the start. 5 more cards will be revealed.

If I start with 3 of one suit, what are the odds of getting at least 2 more of the same suit, in the final five cards?
So if I have 3 clubs, there are 6 clubs left out of 30 unknown cards.

I found this on another forum